Comments on: DateDiff Equivalent in C# – 3 Options

By: Joe P

Joe P — Wed, 13 Jul 2011 01:26:12 +0000

You must reference System.Data.Linq

DateTime startDT = DateTime.Now.AddDays(5);
DateTime endDT = DateTime.Now.AddDays(8);
int monthDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffMonth(startDT, endDT);
int dayDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffDay(startDT, endDT);
int yearDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffYear(startDT, endDT);
int minDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffMinute(startDT, endDT);
int secDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffSecond(startDT, endDT);
int hrsDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffHour(startDT, endDT);
int msDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffMillisecond(startDT, endDT);

By: Joe P

Joe P — Wed, 13 Jul 2011 01:20:46 +0000

You must reference System.Data.Linq

DateTime startDT = DateTime.Now.AddYears(5);
DateTime endDT = DateTime.Now.AddYears(8);
int monthDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffMonth(startDT, endDT);
int dayDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffDay(startDT, endDT);
int yearDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffYear(startDT, endDT);
int minDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffMinute(startDT, endDT);
int secDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffSecond(startDT, endDT);
int hrsDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffHour(startDT, endDT);
int msDiff = System.Data.Linq.SqlClient.SqlMethods.DateDiffMillisecond(startDT, endDT);